Asked by HM
There is a question >
Write the slope intercept form of the equation for the line passing through the points (-6,3) and (0,7)
Now my answer started with >
Slope = 7-3/0-(-6) = Slope = 2/3
Then to find the intercept >
Y=mx+c
3= 2/3(-6) + c
c= 7
In my opinion this is the only way I could think of besides the formula y0-y1=m(x0-x1) and I tried that and I am getting nothing..
So where am I going wrong?
The right answer according to mathlab is > y=3/4x+8
Write the slope intercept form of the equation for the line passing through the points (-6,3) and (0,7)
Now my answer started with >
Slope = 7-3/0-(-6) = Slope = 2/3
Then to find the intercept >
Y=mx+c
3= 2/3(-6) + c
c= 7
In my opinion this is the only way I could think of besides the formula y0-y1=m(x0-x1) and I tried that and I am getting nothing..
So where am I going wrong?
The right answer according to mathlab is > y=3/4x+8
Answers
Answered by
Reiny
Unless you have a typo in your original information, the correct equation in y-intercept slope form is
y = (2/3)x + 7 , which is what you had
As was shown by Jesse, the answer they supplied does not verify , so it is wrong.
Both of the given points satisfy <b>your</b> equation.
As a matter of fact (0,7) is the actual y-intercept , thus the b of the equation.
Trust me!!
y = (2/3)x + 7 , which is what you had
As was shown by Jesse, the answer they supplied does not verify , so it is wrong.
Both of the given points satisfy <b>your</b> equation.
As a matter of fact (0,7) is the actual y-intercept , thus the b of the equation.
Trust me!!
Answered by
HM
Aha, then is must be a technical error in Mathlab. :/
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