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Please can you explain how to do the following: a) a non-smoker with low blood pressure has a plasma chloesterol concentration...Asked by peter
Please can you explain how to do the following:
a) a non-smoker with low blood pressure has a plasma chloesterol concentration of 5mmol per litre. Over a period of time this concentration increases to 8mmol per litre. By how many times has this risk of heart disease increased? Show your working.
b) Two non-smoking men with low blood pressure both have plasma chloesterol concentrations of 5mmol per litre. One of them starts to smoke and the plasma chloesterol concentration of the other increases to 7mmol per litre. Which man is now at the greater risk of heart disease? Explain your answer.
Many thanks
I have changed the subject to maths and science now not biology as my previous post at 2.38pm.
a) a non-smoker with low blood pressure has a plasma chloesterol concentration of 5mmol per litre. Over a period of time this concentration increases to 8mmol per litre. By how many times has this risk of heart disease increased? Show your working.
b) Two non-smoking men with low blood pressure both have plasma chloesterol concentrations of 5mmol per litre. One of them starts to smoke and the plasma chloesterol concentration of the other increases to 7mmol per litre. Which man is now at the greater risk of heart disease? Explain your answer.
Many thanks
I have changed the subject to maths and science now not biology as my previous post at 2.38pm.
Answers
Answered by
muthu
hi PETER, In the first question you didn't say anything about how the risk is measured,and at what level of plasma chloesterol concentration the risk starts with .
and in the second one , how many times that person smokes per day , and how it is effective on the risk
i think this question doesn't have adequate information
by
muthu
vrmuth at gmailcom
and in the second one , how many times that person smokes per day , and how it is effective on the risk
i think this question doesn't have adequate information
by
muthu
vrmuth at gmailcom
Answered by
peter
this is the only information we have been given. hope someone can help.
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