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A 3.0 kg block is pushed along a horizontal floor by a force F of magnitude 19 N at an angle θ = 30° with the horizontal. The c...Asked by Don
A 3.5 kg block is pushed along a horizontal floor by a force of magnitude 15 N at an angle è = 40° with the horizontal. The coefficient of kinetic friction between the block and the floor is 0.25. Calculate the magnitudes of (a) the frictional force on the block from the floor and (b) the block's acceleration.
Answers
Answered by
Can
(a) Friction= u * Normal
Friction= 0.25 * Normal
Normal=15*sin(40) + mg = 43.94
Friction= 0.25 * 43.94 = 10.985N
(b) 19*cos(40) - 10.985 = 0.5 N
F =ma
0.5N = 3.5kg * a
a = 0.14 m/s^2
Friction= 0.25 * Normal
Normal=15*sin(40) + mg = 43.94
Friction= 0.25 * 43.94 = 10.985N
(b) 19*cos(40) - 10.985 = 0.5 N
F =ma
0.5N = 3.5kg * a
a = 0.14 m/s^2
Answered by
Rexix Media
correction on the above answer. It should say 15*cos(40) for part B.
Answered by
Don
Thanks for the help guys, i have finally figured out this question after 8 years. I think I will pass my physics class this time around.
Answered by
John
This honestly is the best thing I've gotten out of physics so far. Made my day. Thank you Don.
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