Asked by Anonymous
From a point 45 meters above level ground, a surveyor measures the angle of depression of an object on the ground at 68°. Approximate the distance from the object to the point on the ground directly beneath the surveyor. (Round your answer to two decimal places.)
Answers
Answered by
Steve
Hint: tan = height/width
Answered by
Anonymous
ok, would you be able to set up for me?
Answered by
STEPHANIE
HELLO???? WHATS THE ANSWER
Answered by
Steve
Well, draw a triangle! I mean, they only gave you two pieces of information. Can't see any way to use it?
At the top of the cliff is point A. At the bottom of the cliff is point B. AB = 45m. Somewhere out along the ground is point C.
Now, angle BAC is 68deg.
BC/45 = tan(68)
BC = 45 tan(68) = 45 * 2.475 = 111.38m
At the top of the cliff is point A. At the bottom of the cliff is point B. AB = 45m. Somewhere out along the ground is point C.
Now, angle BAC is 68deg.
BC/45 = tan(68)
BC = 45 tan(68) = 45 * 2.475 = 111.38m
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.