Point A is 2.0 meters away from a charge of -3.o(Mu) and 3.0 meters away from a charge of +1.5(Mu) as shown.
A) Find the net Electric field at point A
B) Find the total electric potential at point A
Answer This Question
3 answers
please show step by step!
We have no way of knowing the arrangement of the charges. Are they the vertices of a triangle? Are they on a line?
See, the phrase "as shown" means that we can see it. We can't.
I can tell you in general how to do these. Draw a line between A and the first point. The direction of the field is toward the point along that line. The magnitude is E = kq/r^2. Do the same for the other charge only the direction will be away from the point. Now add the two vectors (magnitude AND direction).
Voltage is the same except it has no direction and the magnitude is V = kq/r.
See, the phrase "as shown" means that we can see it. We can't.
I can tell you in general how to do these. Draw a line between A and the first point. The direction of the field is toward the point along that line. The magnitude is E = kq/r^2. Do the same for the other charge only the direction will be away from the point. Now add the two vectors (magnitude AND direction).
Voltage is the same except it has no direction and the magnitude is V = kq/r.
to add the voltages you just add by the way, Voltage is a potential and scalar, not a vector