Asked by ashley
C6H5OH(s) + 7O2(g) --> 6CO2(g) + 3H2O(g)
A 2.000 gram sample of pure phenol, C6H5OH(s), is completely burned according to the equation above. If the volume of the combustion chamber is 10.0L, calculate the final pessure in the container when the temperature is 110 degrees C. (Assume no oxygen remains unreacted and that all products are gaseous)
A 2.000 gram sample of pure phenol, C6H5OH(s), is completely burned according to the equation above. If the volume of the combustion chamber is 10.0L, calculate the final pessure in the container when the temperature is 110 degrees C. (Assume no oxygen remains unreacted and that all products are gaseous)
Answers
Answered by
DrBob222
Convertr 2.000 g phenol to mols. mols = grams/molar mass.
Convert mols phenol to mols CO2 and mols H2O using the coefficients in the balanced equation.
Use PV = nRT to calculate P (in atmospheres). n is the total mols calculated above, V is known, R is known (0.08205 L*atm/mol*K) and T is known. Don't forget to convert 110 degrees C to Kelvin. Post your work if you get stuck.
Convert mols phenol to mols CO2 and mols H2O using the coefficients in the balanced equation.
Use PV = nRT to calculate P (in atmospheres). n is the total mols calculated above, V is known, R is known (0.08205 L*atm/mol*K) and T is known. Don't forget to convert 110 degrees C to Kelvin. Post your work if you get stuck.
Answered by
paul
1.2
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