Asked by vicki
find an equation of the tangent line to the curve at y=2x^3+5x, (-1, 3)
Answers
Answered by
Reiny
dy/dx = 6x + 5
so at (-1,3), dy/dx = -6+5 = -1
slope = -1, point on line is (-1,3)
3 = (-1)(-1) + b in y = mx+b
2 = b
equation of tangent:
y = -x + 2
so at (-1,3), dy/dx = -6+5 = -1
slope = -1, point on line is (-1,3)
3 = (-1)(-1) + b in y = mx+b
2 = b
equation of tangent:
y = -x + 2
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