Asked by Junior
Find an equation of the tangent line to the curve at each given point.
x = t^2 − 4, y = t^2 − 2t
at (0, 0) =
at (−3, −1) =
at (−3, 3) =
x = t^2 − 4, y = t^2 − 2t
at (0, 0) =
at (−3, −1) =
at (−3, 3) =
Answers
Answered by
oobleck
dy/dx = (2t-2)/(2t) = 1 - 1/t
at (0,0) t=2, so dy/dx = 1 - 1/2 = 1/2
Do the other two points in like wise
at (0,0) t=2, so dy/dx = 1 - 1/2 = 1/2
Do the other two points in like wise
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