Asked by Christine
find an equation of the tangent line to the parabola at the given point..show work
y=(-2)x^2
(-1,-2)
y=(-2)x^2
(-1,-2)
Answers
Answered by
bobpursley
I assume you know enought calc to take the derivative.
y'=slope=-4x=4
y=4x+b
solve for b a the point, and you have the line
y'=slope=-4x=4
y=4x+b
solve for b a the point, and you have the line
Answered by
Christine
dont know how to find the derivitive
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