Asked by Matt
1. Evaluate the indefinite integral
([6x^2 + 12x^(3/2) +4x+9]/sqrt x)dx.
Answer = + C
2. Evaluate the indefinite integral
(12sin x+4tan x)dx.
Answer = + C
3. Evaluate the indefinite integral.
(x^7)e^(x^8)dx.
Answer = + C
Thank you for helping.
([6x^2 + 12x^(3/2) +4x+9]/sqrt x)dx.
Answer = + C
2. Evaluate the indefinite integral
(12sin x+4tan x)dx.
Answer = + C
3. Evaluate the indefinite integral.
(x^7)e^(x^8)dx.
Answer = + C
Thank you for helping.
Answers
Answered by
Reiny
∫(6x^2 + 12x^(3/2) +4x+9]/√x)
= ∫ 6x^(3/2) + 12x + 4x^(1/2) + 9x^(-1/2) dx
= (12/5)x^(5/2) = 6x^2 + (8/3)x^(3/2) + 18x^(1/2) + c
∫ (12sinx + 4tanx) dx
= ∫( 12sinx + 4 sinx/cosx) dx
= -12cosx - 4ln(cosx) + c
∫ (x^7) e^(x^8) dx
= (1/8) e^(x^8) + c
= ∫ 6x^(3/2) + 12x + 4x^(1/2) + 9x^(-1/2) dx
= (12/5)x^(5/2) = 6x^2 + (8/3)x^(3/2) + 18x^(1/2) + c
∫ (12sinx + 4tanx) dx
= ∫( 12sinx + 4 sinx/cosx) dx
= -12cosx - 4ln(cosx) + c
∫ (x^7) e^(x^8) dx
= (1/8) e^(x^8) + c
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