Asked by Hailey
6) Evaluate the indefinite integral.
∫cosx/(7sinx+35)dx
∫cosx/(7sinx+35)dx
Answers
Answered by
Steve
let u = 7sinx+35
du = 7cosx
and the integrand now becomes
1/7 du/u
du = 7cosx
and the integrand now becomes
1/7 du/u
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