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For the reaction4NH3(g) + 3O2(g) -> 2N2(g) + 6H2O(g) , K = 10^80 at a certain temperature. Initially, all reactants and products
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Given:Equation #1: 4NH3(g) + 5O2(g) = 4NO(g) + 6H2O; ΔH of reaction = -1170 kJ Equation #2: 4NH3(g) + 3O2(g) = 2N2(g) + 6H2O;
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