Asked by Jaskson

Ninety kilojoules of heat were added to a 2.0-kg piece of wood whose temperture then rose from 20 degrees Celsius to 48 degrees Celcius. What was the specific heat of the wood?

Answered by drwls
Review the definition of specific heat.

Spec. Ht. = (heat added)/[(mass)*(deltaT)]

DeltaT is the temperature increase, which in your case is 28 C.

Perform that calculation to obtain the answer.
Answered by Anonymous
87
Answered by John
31
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