Question

how many kilojoules of heat must be transferred to a 480 g aluminum pizza pan to raise its temperature from 22 degree c to 234 degree c? The specific heat of aluminum in this temperature range is 0.97 J/g degree C.

Answer 1

recall that heat absorbed released is given by
Q = mc*(T2 - T1)
where
m = mass (in g)
c = specific heat capacity (in J/g-k)
T = temperature (in C or K)
*note: Q is (+) when heat is absorbed and (-) when heat is released.
substituting,
Q = (480)*(0.97)*(234 - 22)
Q = 98707 J = 98.7 kJ

hope this helps~ :)

Answer 2

iqj

Answer 3

I hate science