Asked by cait
car comes to a stop over distance of 30.0m after the driver applies brakes. If the car decelerates @ contant rate of 3.50m/s2, what was the car's origianl sped?
Answers
Answered by
bobpursley
Vf^2=vi^2+2ad a=-3.5m/s^2, d=30, solve for vi
Answered by
Anonymous
210
Answered by
anonymous
14.5
Answered by
Anonymous
14.5
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