x^2 - 4 = 2x-10
x^2-2x+6 = 0
There you go... solve by factor or that quadratic formula.
Solve the equation for x: x² - 4 = 2^(x - 5)?
2 answers
If I read your equation correctly, you said:
x2 - 4 = 2x-5
If that is the case, then the solution is much more complicated than Jake1214 has suggested.
I ran it through my trusty homemade "Newton Method" equation solver and got approximate answers of
x = 2.031693
x = -2.001951
and another answer between x = 12.1 and 12.2 (it kept giving me an overflow error if I tried to refine the domain, I wrote my program in an archaic version (1970's) of GWBasic)
If you make a rough graph of
f(x) = x^2 - 4 - 2^(x-5), it will verify that.
x2 - 4 = 2x-5
If that is the case, then the solution is much more complicated than Jake1214 has suggested.
I ran it through my trusty homemade "Newton Method" equation solver and got approximate answers of
x = 2.031693
x = -2.001951
and another answer between x = 12.1 and 12.2 (it kept giving me an overflow error if I tried to refine the domain, I wrote my program in an archaic version (1970's) of GWBasic)
If you make a rough graph of
f(x) = x^2 - 4 - 2^(x-5), it will verify that.