Asked by Anonymous
Solve the equation for x: x² - 4 = 2^(x - 5)?
Answers
Answered by
Jake1214
x^2 - 4 = 2x-10
x^2-2x+6 = 0
There you go... solve by factor or that quadratic formula.
x^2-2x+6 = 0
There you go... solve by factor or that quadratic formula.
Answered by
Reiny
If I read your equation correctly, you said:
x<sup>2</sup> - 4 = 2<sup>x-5</sup>
If that is the case, then the solution is much more complicated than Jake1214 has suggested.
I ran it through my trusty homemade "Newton Method" equation solver and got approximate answers of
x = 2.031693
x = -2.001951
and another answer between x = 12.1 and 12.2 (it kept giving me an overflow error if I tried to refine the domain, I wrote my program in an archaic version (1970's) of GWBasic)
If you make a rough graph of
f(x) = x^2 - 4 - 2^(x-5), it will verify that.
x<sup>2</sup> - 4 = 2<sup>x-5</sup>
If that is the case, then the solution is much more complicated than Jake1214 has suggested.
I ran it through my trusty homemade "Newton Method" equation solver and got approximate answers of
x = 2.031693
x = -2.001951
and another answer between x = 12.1 and 12.2 (it kept giving me an overflow error if I tried to refine the domain, I wrote my program in an archaic version (1970's) of GWBasic)
If you make a rough graph of
f(x) = x^2 - 4 - 2^(x-5), it will verify that.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.