a uniformly accelerating train passes a green light signal at25.0 km/hr it passes a second light 125m farther down the track 12.0s later what is the trains acceleration? what is the trains velocity at the second light?

Answer 1

x = Vi t + (1/2) a t^2

125 = (25000/3600)(12) + .5 * a * 144
solve for a

then
v = Vi + a t

Answer 2

where did you get the 144

Answer 3

ok i get

Answer 4

correct me if im wrong solve for a = 102
and v = 1249

Answer 5

A = 51.15
V= 638.8