Asked by dan

a uniformly accelerating train passes a green light signal at25.0 km/hr it passes a second light 125m farther down the track 12.0s later what is the trains acceleration? what is the trains velocity at the second light?
Answered by Damon
x = Vi t + (1/2) a t^2

125 = (25000/3600)(12) + .5 * a * 144
solve for a

then
v = Vi + a t
Answered by dan
where did you get the 144
Answered by dan
ok i get
Answered by dan
correct me if im wrong solve for a = 102
and v = 1249
Answered by dan
A = 51.15
V= 638.8
There are no AI answers yet. The ability to request AI answers is coming soon!