Asked by arty
a train slows down from 104m/s to 76m/s with constant decceleration in 440m. 1) what is the acceleration of the train? 2) how long does it take the train to travel this distance? 3) plot the position, velocity and acceleration of the train during this time interval as a function of time, using the initial position of the train as the origin.
Answers
Answered by
bobpursley
Vf^2=Vi^2+2ad solve for a
then 2) vf=vi+at solve for t.
then 2) vf=vi+at solve for t.
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