Asked by Laura
I am having trouble balancing the following equation using the Ion-Electron Method.
Se(solid) + HNO3(aqueous) ----> SeO2(solid) + NO(gas) + H2O(liquid)
Can you explain the steps that you have to take to solve it?
Se(solid) + HNO3(aqueous) ----> SeO2(solid) + NO(gas) + H2O(liquid)
Can you explain the steps that you have to take to solve it?
Answers
Answered by
DrBob222
http://www.chemteam.info/Redox/Balance-HalfReactions-Base.html
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