Asked by ALISON
You carefully weigh out 19.00 of powder and add it to 76.95 of solution. You notice bubbles as a reaction takes place. You then weigh the resulting solution and find that it has a mass of 88.16 . The relevant equation is
CaCO3+2HCl ----> H2O + CO2 + CaCl2
Assuming no other reactions take place, what mass of was produced in this reaction?
I have no idea how to attempt to solve this problem, i tried getting moles of carbon but I'm lost. Help please.
CaCO3+2HCl ----> H2O + CO2 + CaCl2
Assuming no other reactions take place, what mass of was produced in this reaction?
I have no idea how to attempt to solve this problem, i tried getting moles of carbon but I'm lost. Help please.
Answers
Answered by
ALISON
oops...* Assuming no other rxn's what mass of CO2 was produced in this rxn?
Answered by
DrBob222
Do you not believe in units? Is that 19.00g, 76.95g, and 88.16g? If so, then
19.00g + 76.95g on the left.
Mass H2O and CaCl2 on the right = 88.16g. So the difference must be the mass CO2 on the right.
19.00g + 76.95g on the left.
Mass H2O and CaCl2 on the right = 88.16g. So the difference must be the mass CO2 on the right.
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