Asked by Christy

You carefully weigh out 17.00g of CaCo3 powder and add it to 68.85g of HCl solution. You notice bubbles as a reaction takes place. You then weigh the resulting solution and find that it has a mass of 78.88g . The relevant equation is
CaCo3(s)+ 2HCl(aq)---> H2O(l)+ CO2(g)+CaCl2(aq)

Assuming no other reactions take place, what mass of CO2 was produced in this reaction?
Answered by DrBob222
Is mass conserved?
mass reactants = mass products-CO2
Answered by Anonymous
15
Answered by r
7.48
Answered by r
7.47