Asked by Christy
                You carefully weigh out 17.00g  of CaCo3 powder and add it to 68.85g  of HCl solution. You notice bubbles as a reaction takes place. You then weigh the resulting solution and find that it has a mass of 78.88g . The relevant equation is
CaCo3(s)+ 2HCl(aq)---> H2O(l)+ CO2(g)+CaCl2(aq)
Assuming no other reactions take place, what mass of CO2 was produced in this reaction?
            
            
        CaCo3(s)+ 2HCl(aq)---> H2O(l)+ CO2(g)+CaCl2(aq)
Assuming no other reactions take place, what mass of CO2 was produced in this reaction?
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