A helicopter is ascending (moving upwards) at a constant velocity of 8 m/s. At a height of 90m, a passenger opens a window and drops a package to the ground below. How long does it take the package to hit the ground and how fast is it moving just before impact?

1 answer

d = Vo*t + 0.5gt^2 = 90m,
0 + 0.5*9.8*t^2 = 90,
4.9t^2 = 90,
t^2 = 18.36,
t = 4.29s.

Vf = Vo + gt,
Vf = 0 + 9.8*4.29 = 42m/s.