Question

A helicopter is ascending (moving upwards) at a constant velocity of 8 m/s. At a height of 90m, a passenger opens a window and drops a package to the ground below. How long does it take the package to hit the ground and how fast is it moving just before impact?

Answer 1

vi=8m/s
g= -9.8m/s^2

hf=hi+Vi*t-1/2 9.8t^2 solve for t to hit ground

how fast?

Vf=Vi-9.8 t