(x-4)^2+y^2=16
x^2-8x+16+y^2=16
x^2+y^2=8x
r^2=8r*cos(theta)
r=8cos(theta)
Write the rectangular equation in polar form.
(x – 4)2 + y2 = 16
2 answers
(x–4)2
49
+
Y2
16
=1?
49
+
Y2
16
=1?
(x – 4)2 + y2 = 16
2 answers