Asked by Heather
Find a rectangular equation for the plane curve defined by the parametric equations.
x = sin(theta)
y = 3cos(theta)
x = sin(theta)
y = 3cos(theta)
Answers
Answered by
Reiny
we know sinØ = y/r and cosØ = x/r
and tanØ = y/x
then for the given:
sinØ = x = y/r
rx = y ---> r = y/x
3cosØ = y = 3x/r
ry = 3x
(y/x)y = 3x
y^2 = 3x^2
y = ±√3 x
and tanØ = y/x
then for the given:
sinØ = x = y/r
rx = y ---> r = y/x
3cosØ = y = 3x/r
ry = 3x
(y/x)y = 3x
y^2 = 3x^2
y = ±√3 x
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