The width of a rectangle is 2ft less than the length. The area is 8ft^2.Find the length and the width.

The factors of 8 are:

8, 1
4, 2

I got the width is 2 and the length is 4

Right again!

To find the length and width of the rectangle, we can use the formula for the area of a rectangle, which is length multiplied by width.

Let's assume the length of the rectangle is x. According to the problem, the width is 2 feet less than the length. Therefore, the width would be (x - 2).

We can now form an equation for the area of the rectangle, which is 8 square feet:

x * (x - 2) = 8

To solve this equation, we can start by simplifying it:

x^2 - 2x = 8

Rearranging the equation:

x^2 - 2x - 8 = 0

Now, we can solve this quadratic equation. We can do this by factoring, completing the square, or using the quadratic formula. In this case, let's solve it by factoring:

(x - 4)(x + 2) = 0

This gives us two possible solutions:

x - 4 = 0 or x + 2 = 0

Solving for x:

x = 4 or x = -2

Since a length cannot be negative, we discard the x = -2 solution.

Hence, the length of the rectangle is 4 feet.

Now, we can find the width by substitute the value of x into the expression we set for the width:

Width = x - 2 = 4 - 2 = 2

Therefore, the width of the rectangle is 2 feet.

To summarize:
The width is 2 ft.
The length is 4 ft.