Question
The rectangle below has an area of 30k^3+6k^2
The width of the rectangle (in meters) is equal to the greatest common monomial factor of 30k^3 and 6k^2
What is the width and length of the rectangle?
Width:6k^2
Length:
I couldn't find the length I need to be explained of how to find it because I feel like I know how to do it but its playing with me.
The width of the rectangle (in meters) is equal to the greatest common monomial factor of 30k^3 and 6k^2
What is the width and length of the rectangle?
Width:6k^2
Length:
I couldn't find the length I need to be explained of how to find it because I feel like I know how to do it but its playing with me.
Answers
Steve
30k^3+6k^2 = (6k^2)(5k+1)
salman
The rectangle below has an area of 30k^3+6k^230k
3
+6k
2
square meters.
The width of the rectangle (in meters) is equal to the greatest common monomial factor of 30k^330k
3
and 6k^26k
2
.
What is the length and width of the rectangle?
\text{Width} = Width=
meters
\text{Length} = Length=
meters
3
+6k
2
square meters.
The width of the rectangle (in meters) is equal to the greatest common monomial factor of 30k^330k
3
and 6k^26k
2
.
What is the length and width of the rectangle?
\text{Width} = Width=
meters
\text{Length} = Length=
meters
Anonymous
(6k2)(5tk1)