Asked by Ed
                The rectangle below has an area of 30k^3+6k^2
The width of the rectangle (in meters) is equal to the greatest common monomial factor of 30k^3 and 6k^2
What is the width and length of the rectangle?
Width:6k^2
Length:
I couldn't find the length I need to be explained of how to find it because I feel like I know how to do it but its playing with me.
            
        The width of the rectangle (in meters) is equal to the greatest common monomial factor of 30k^3 and 6k^2
What is the width and length of the rectangle?
Width:6k^2
Length:
I couldn't find the length I need to be explained of how to find it because I feel like I know how to do it but its playing with me.
Answers
                    Answered by
            Steve
            
    30k^3+6k^2 = (6k^2)(5k+1)
    
                    Answered by
            salman
            
    The rectangle below has an area of 30k^3+6k^230k 
3
+6k
2
square meters.
The width of the rectangle (in meters) is equal to the greatest common monomial factor of 30k^330k
3
and 6k^26k
2
.
What is the length and width of the rectangle?
 
 
\text{Width} = Width=
meters
\text{Length} = Length=
meters
    
3
+6k
2
square meters.
The width of the rectangle (in meters) is equal to the greatest common monomial factor of 30k^330k
3
and 6k^26k
2
.
What is the length and width of the rectangle?
\text{Width} = Width=
meters
\text{Length} = Length=
meters
                    Answered by
            Anonymous
            
    (6k2)(5tk1)
    
                                                    There are no AI answers yet. The ability to request AI answers is coming soon!
                                            
                Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.