Asked by Laynette

The diameters of apples in a certain orchard are normally distributed with a mean of 4.77 inches and a standard deviation of 0.43 inches. Show all work.
(A) What percentage of the apples in this orchard is larger than 4.71 inches?
(B) A random sample of 100 apples is gathered and the mean diameter is calculated. What is the probability that the sample mean is greater than 4.71 inches?
Answered by PsyDAG
A. Z = (score-mean)/SD

Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion related to the Z score.

B. Same process except that, instead of SD, you use SEm = SD/√n
Answered by denise
once again I am not getting this.
assume that the population of heights of male college students is normally distibuted with a mean of 69.09 and standard deviation of 4.71. A random sample of 92 heights is obtained. find the mean and standard error of the x distribution.
find P(x>68.5)
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