2(x+(x+5))=58
2(2x+5)=58
4x+10=58
then subtract 10 from both side, which gives you,
4x=48
here x=12 and the length is x+5 which is 12+5=17
L:17 and B:12
I know the formula for Triangle Perimeter is 2(L+W) and the L is +5 more than the W but I can't write the equation for it. This is what I was thinking 58= 4x-5
Thanks again.
2(2x+5)=58
4x+10=58
then subtract 10 from both side, which gives you,
4x=48
here x=12 and the length is x+5 which is 12+5=17
L:17 and B:12
Let's assume the width of the rectangle is x cm.
According to the given information, the length of the rectangle is 5 cm greater than its width. Therefore, the length can be expressed as (x + 5) cm.
The perimeter of a rectangle is given by the formula: Perimeter = 2(Length + Width).
Substituting the values, we get:
58 = 2[(x + 5) + x]
Simplifying the equation:
58 = 2(2x + 5)
58 = 4x + 10
48 = 4x
x = 12
Therefore, the width of the rectangle is 12 cm, and the length is (12 + 5) = 17 cm.
Let's say the width of the rectangle is W cm. According to the problem, the length of the rectangle is 5 cm greater than its width, so the length would be (W + 5) cm.
The perimeter of a rectangle is given by the formula: P = 2(L + W)
We are given that the perimeter is 58 cm, so we can substitute these values into the formula:
58 = 2((W + 5) + W)
Now, we can simplify and solve for W:
58 = 2(2W + 5)
58 = 4W + 10
48 = 4W
W = 12
So the width of the rectangle is 12 cm. Now, we can plug this value back into the equation to find the length:
L = W + 5
L = 12 + 5
L = 17
Therefore, the dimensions of the rectangle are 12 cm (width) and 17 cm (length).