2(x+(x+5))=58
2(2x+5)=58
4x+10=58
then subtract 10 from both side, which gives you,
4x=48
here x=12 and the length is x+5 which is 12+5=17
L:17 and B:12
The length of a rectangle is 5 cm greater than it width. The perimeter is 58 cm. What are the dimension of the rectangle?
I know the formula for Triangle Perimeter is 2(L+W) and the L is +5 more than the W but I can't write the equation for it. This is what I was thinking 58= 4x-5
Thanks again.
2 answers
perimeter=2(l+W)=2(w+5+w)
6 answers