Asked by Gabrielle
Mercury concentration in a polluted lake is 0.0125 micrograms/L. What is the total mass in kilograms of mercury in the lake if the lake is approximately circular witha diameter of 10 miles and an average depth of 50 ft.?
Answers
Answered by
DrBob222
Convert 5 mi radius to cm and 50 ft depth to cm, then pi*r^2*h will give you the volume in cc. Then convert cc to L and multiply by 0.0125 to give micrograms Hg in the lake. Convert to kg. Post your work if you get stuck.
Answered by
Jackie Chan
2.2345x10^-2kg
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