Asked by jan
there are 80 students enrolled in statistics. (a)you and 11 other earned the same score. what percent of the class received your score? (b)forty percent of the class received a grade of C. how many students received a C? (c) only 7.5% of the class received a D. how many students is this? A student claims that .5% of the class failed. why is this impossible?
Answers
Answered by
Martin
a) 11 + 1 (you) = 12. 12/80 = 0.15 = 15%
b)40% = 0.4, 0.4 x 80 = 32.
c) 7.5% = 0.075, 0.075 x 80 = 6
Also, 0.5% x 80 = 0.005 x 80 = 0.4 students, which doesn't make sense.
b)40% = 0.4, 0.4 x 80 = 32.
c) 7.5% = 0.075, 0.075 x 80 = 6
Also, 0.5% x 80 = 0.005 x 80 = 0.4 students, which doesn't make sense.
Answered by
Anonymous
fill in missing proportion for normal distribution.
1. .40
2. .10
1. .40
2. .10
Answered by
bob
see a.) if .15 = 15%, which is correct, then .5 is 50% not .005, therefore, 4 students failed but, we have calculated that 65% of the students have a grade above failing. The claim that 50% failed is false, there is only 35% left who have a grade other than the D and some other grade different than the 15% that is, 12 of 80 or 12/80.
Answered by
Megan
72%
Answered by
Jason Waterman
If the class inclues you ... then how can it be a pool of 80 ? the pool would have to be 79 and only 11 students got your score ?