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The diameter of an electric cable is normally distributed, with a mean of 0.8 inch and a standard deviation of 0.01 inch. What...Asked by apryl
The diameter of an electric cable is normally distributed, with a mean of 0.8 inch and a standard deviation of 0.01 inch. What is the probability that the diameter will exceed 0.82 inch? (Give the answer to four decimal places.)
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Answered by
Martin
0.82 - 0.8 = 0.02
0.02/0.01 = 2 standard deviations
You check a normal distribution table (unless you were provided with the value for 2 standard deviation already)
You get : Greater than 2 standard deviation = 1 - 0.9772 = 0.0228
0.02/0.01 = 2 standard deviations
You check a normal distribution table (unless you were provided with the value for 2 standard deviation already)
You get : Greater than 2 standard deviation = 1 - 0.9772 = 0.0228
Answered by
mj
The diameter of an electric cable is normally distributed, with a mean of 0.8 inch and a standard deviation of 0.01 inch. What is the probability that the diameter will exceed 0.81 inch
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