Asked by Brit
For the function f(x)=1/(x+1), verify f(x) is one-to-one, then calculate f^-1 (1/4) and (f^-1)' (1/4)
Answers
Answered by
bobpursley
the inverse
y=1/(x+1)
x=1/(y+1)
y=1/x -1
y(1/4)=3
y'=-1/x^2
y'(1/4)=-16
y=1/(x+1)
x=1/(y+1)
y=1/x -1
y(1/4)=3
y'=-1/x^2
y'(1/4)=-16
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