Asked by qwerty123
a triangle has vertices A, B, and C, and the respective opposite sides have lengths a,b, and c. If a=1, b=3, and C=60, then sin^2(B) is equal to ?
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Answered by
qwerty123
I figured out the answer to my own question. 9(0.75)/c^2=6.75/c^2=(sin^2)B.
Using law of cosines, c^2=7. 6.75/7=27/28.
Using law of cosines, c^2=7. 6.75/7=27/28.
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