Asked by Laura
A bus accelerates at 1.4 m/s2 from rest for 10 s. It then travels at constant speed for 26 s, after which it slows to a stop with an acceleration of magnitude 1.4 m/s2.
(a) What is the total distance that the bus travels?
(b) What was its average velocity?
(a) What is the total distance that the bus travels?
(b) What was its average velocity?
Answers
Answered by
bobpursley
distance=1/2*1.4*10^2 + 1.4*10*26+ gets you the distance till it starts to brake.
Now to deaccelerate from that velocity, it takes 10 sec (think on that).
distance braking= vi*t-1/2 a t^2 or
1.4*10*10-1/2 1.4 10^2=70m
add that to the above distance.
avg velocity= distance/total time=totaldistance/(10+26+10)
Now to deaccelerate from that velocity, it takes 10 sec (think on that).
distance braking= vi*t-1/2 a t^2 or
1.4*10*10-1/2 1.4 10^2=70m
add that to the above distance.
avg velocity= distance/total time=totaldistance/(10+26+10)
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