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Asked by
Kelly
integral of (1-(sinx)^2))/(cosx)dx
i don't know what to make my "u" for u-substitution
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Answered by
Damon
ah
(1-(sinx)^2)) = cos^2 x
Unless I am mistaken or there is a typo all you have is
cos x dx
which is sin x + c
Answered by
Kelly
Oh! I didn't realize it was so simple. Thank you!
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