Asked by sonu
what will be the focus and directrix of parabola y*y = -16x.
Answers
Answered by
Henry
Given: y*y = -16x.
y^2 = -16x,
x = -(1/16)y^2, x-parabola.
a = -(1/16),
4a = -(4/16) = -(1/4),
1/4a = -4.
[1/4a] = 4.
V(h,k), k = Yv = -b/2a = 0/2a = 0.
h = -(1/16)0^2 = 0.
F(X1,0), V(0,0), D(X2,0).
X1 = k - [1/4a] = 0 - 4 = -4.
X2 = k + [1/4a] = 0 + 4 = 4.
F(-4,0), V(0,0), D(4,0).
y^2 = -16x,
x = -(1/16)y^2, x-parabola.
a = -(1/16),
4a = -(4/16) = -(1/4),
1/4a = -4.
[1/4a] = 4.
V(h,k), k = Yv = -b/2a = 0/2a = 0.
h = -(1/16)0^2 = 0.
F(X1,0), V(0,0), D(X2,0).
X1 = k - [1/4a] = 0 - 4 = -4.
X2 = k + [1/4a] = 0 + 4 = 4.
F(-4,0), V(0,0), D(4,0).
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