(i) Solve the equation 3y^2-5y-2=0

Question

(ii) hence, solve the equation, 3(1/x-1)^2 -5(1/x-1)-2=0

Answer 1

I will treat this as one question.

From the second part, let y = (1/x - 1).
The second equation thus becomes
3y^2 - 5y - 2 = 0 , which is the first one
(3y + 1)(y - 2) = 0
y = -1/3 or y = 2 , which answers the first part

then 1/x - 1 = -1/3 or 1/x - 1 = 2
1/x = 2/3 or 1/x = 3

x = 3/2 or x = 1/3

Answer 2

z + (-3 and 2 5ths)= -4 and 1 10ths please solve