Asked by Yolie
Solve the equation
-5e^-x + 9 = 6
I subtracted 9 to both sides and got:
-5e^-x= -3 < this is where I'm stuck at.
-5e^-x + 9 = 6
I subtracted 9 to both sides and got:
-5e^-x= -3 < this is where I'm stuck at.
Answers
Answered by
Anonymous
- 5e ^ ( - x ) + 9 = 6
- 5e ^ ( - x ) = 6 - 9
- 5e ^ ( - x ) = - 3 Divide both sides by - 5
e ^ ( - x ) = 3 / 5
Take the natural logarithm of both sides:
- x = - log (5 / 3 )
Divide both sides by -1:
x = log ( 5 / 3 )
x = 0.510826
Remark:
log mean natural logarithm
- 5e ^ ( - x ) = 6 - 9
- 5e ^ ( - x ) = - 3 Divide both sides by - 5
e ^ ( - x ) = 3 / 5
Take the natural logarithm of both sides:
- x = - log (5 / 3 )
Divide both sides by -1:
x = log ( 5 / 3 )
x = 0.510826
Remark:
log mean natural logarithm
Answered by
Yolie
Tysm :D
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