Asked by Kristi
A 3.30-g bullet, traveling at a speed of 492 m/s, strikes the wooden block of a ballistic pendulum, such as that in Figure 7.14. The block has a mass of 232 g. (a) Find the speed of the bullet/block combination immediately after the collision. (b) How high does the combination rise above its initial position?
Answers
Answered by
drwls
1) Use the law of conservation of momentum to get the bullet_block velocity after collision, Vfinal.
3.30*492 = Vfinal*(3.30 + 232)
2) Use the law of conservation of energy to calculate how far up the bullet and block rise, H
g H = Vfinal^2/2
3) Show your work if further assistance is required
3.30*492 = Vfinal*(3.30 + 232)
2) Use the law of conservation of energy to calculate how far up the bullet and block rise, H
g H = Vfinal^2/2
3) Show your work if further assistance is required
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