Asked by John
A 0.13 kg bullet traveling at 614 m/s hits a 5.7 kg block of wood and stays in the wood. What is the velocity (speed)of the wood block immediately after the bullet hits it
Answers
Answered by
drwls
Use the law of conswervation of mometnum.
0.13 * 614 = (0.13 + 5.7)*Vfinal
Solve for Vfinal
0.13 * 614 = (0.13 + 5.7)*Vfinal
Solve for Vfinal
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