Asked by anna

I am having trouble figuring out this question

Jan observes a buoy bobbing up and down through a total amplitude of 8 feet. Beginning at the top of the wave, if the buoy completes a full cycle every 8 seconds, what is the height of the buoy relative to its lowest point after 12 seconds?

I tried making a function out of what was given to me but I am missing so much information I don't understand dhow it would work.

Answers

Answered by bobpursley
amplitude=1/2 full swing=4feet
period = 8 seconds, or freq=1/8 second, or w=2PI/8 or PI/4 rad/sec

h=4cos(wt)=4cos(PI/4 * 12)=4cos 3PI

check that.

another way: the time is 1.5 periods, which means it has to be on the lowest point.

sketch the graph
Answered by anna
where did the 12 come from?
Answered by anna
oops sorry never mind
Answered by anna
How do you know to use cos and not sine?
Answered by Damon
cos has value of 1 at t = 0 so that would be at the top of the wave as the problem stated.
Sin of 0 is 0 so that is not what you want.
You could do the same thing with a phase shift of pi/2 because
sin (90 deg -a) = cos a
sin (pi/2 - pi t/4) = cos (pi t/4)
Answered by anna
oh I see thank you very much I totally get it now
Answered by Damon
By the way remember it is relative to the lowest point, not zero, so it is -4 + whatever your answer is.

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