Solve the logarithmic equation.

Question

log2(4x)-log2(x+3)=1

Answer 1

log₂(4x - log₂(x+3) = 1
log₂(4x/(x+3)) = 1
4x/(x+3) = 2^1 = 2
4x = 2x+6
2x = 6
x = 3

Answer 2

Thanks for your help!! I knew how to start, just wasn't sure the steps to go!