Asked by Meghan

Solve the logarithmic equation.

log2(4x)-log2(x+3)=1

Answers

Answered by Reiny
log<sub>2</sub>(4x - log<sub>2</sub>(x+3) = 1
log<sub>2</sub>(4x/(x+3)) = 1
4x/(x+3) = 2^1 = 2
4x = 2x+6
2x = 6
x = 3
Answered by Meghan
Thanks for your help!! I knew how to start, just wasn't sure the steps to go!
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