Question
Solve the logarithmic equation.
log2(4x)-log2(x+3)=1
log2(4x)-log2(x+3)=1
Answers
Reiny
log<sub>2</sub>(4x - log<sub>2</sub>(x+3) = 1
log<sub>2</sub>(4x/(x+3)) = 1
4x/(x+3) = 2^1 = 2
4x = 2x+6
2x = 6
x = 3
log<sub>2</sub>(4x/(x+3)) = 1
4x/(x+3) = 2^1 = 2
4x = 2x+6
2x = 6
x = 3
Meghan
Thanks for your help!! I knew how to start, just wasn't sure the steps to go!