Babe Ruth steps to the plate and casually points to left center field to indicate the location of his next home run. The mighty Babe holds his bat across his shoulder, with one hand holding the small end of the bat. The bat is horizontal, and the distance from the small end of the bat to the shoulder is 22.5 cm . The bat has a mass of 1.10 kg and has a center of mass that is 67.0 cm from the small end of the bat.

Question

a) Find the magnitude of the force exerted by the hand?
b)Find the magnitude of the force exerted by the shoulder.

and their directions

Thanks!

Answer 1

hand at x = 0
shoulder at x = .225meters
bat at .67meters

hand (moments about shoulder = 0)
1.1 (9.8)(.67 - .225) = Fh(.225)
Fh is down

shoulder (moments about hand = 0)
1.1(9.8)(.67) = Fs (22.5)
Fs is up