Asked by Danielle
I'm trying to calculate probablity of dependent and independent events. For example, from 3 nickels, 2 dimes, and 5 quarters, what is the probability of drawing 1 nickel, 1 dime, and 1 quarter in that order without replacement? Or drawing the same in any order with replacement? I don't understand the difference in how to calculate them. Thanks for any help!
Answers
Answered by
PsyDAG
Without replacement, the probability of drawing the nickel is 3/10, the dime is 2/9 and the quarter is 5/8. Mulitply the probability of the three events to get the probability that all would occur. Each probability is dependent on the previous event.
With replacement, the same probabilities are 3/10, 2/10 and 5/10. Multiply again. The probabilities are independent of each other, so order is not important.
I hope this helps. Thanks for asking.
With replacement, the same probabilities are 3/10, 2/10 and 5/10. Multiply again. The probabilities are independent of each other, so order is not important.
I hope this helps. Thanks for asking.
Answered by
Danielle
Very helpful! Thank you!
As another part of the same type question...what if they have to be selected in a certain order (1 nickel, then 1 dime, then 1 quarter) as opposed to a nickel, a dime, and a quarter in any order? Thanks for your time!
As another part of the same type question...what if they have to be selected in a certain order (1 nickel, then 1 dime, then 1 quarter) as opposed to a nickel, a dime, and a quarter in any order? Thanks for your time!
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