Asked by Sammy
A cylindrical metal can with a radius of 4.25 cm is floating upright in water. A rock is placed in the can, causing it to sink 0.0230 m deeper into the water. What is the weight of the rock?
Answers
Answered by
drwls
The mass of additional water displaced equals the mass of the rock.
That equals
pi*R^2*2.3 cm^3* 1.00 g/cm^3 = 65.3 grams = 0.0653 kg
For the rock's weight in newtons, multiply that by 9.8.
That equals
pi*R^2*2.3 cm^3* 1.00 g/cm^3 = 65.3 grams = 0.0653 kg
For the rock's weight in newtons, multiply that by 9.8.
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