Asked by birock
A cylindrical metal radius 7cm and height 15cm has its centre drilled with a hole of 5cm in cross-section. If 152cm(cube) of d metal weight 125kg, what is the weight of d hallowed cylinder?
How do I solve this please?
How do I solve this please?
Answers
Answered by
bobpursley
figure out the volume of the inner drilled out hole (PI*5^2*15 cm^3)
then mass of metal out of hole
= density*volume
density= 125kg/152 kg/cm^3 Wow that is a dense metal
mass metal out ofhole=density*volumehole
then mass of metal out of hole
= density*volume
density= 125kg/152 kg/cm^3 Wow that is a dense metal
mass metal out ofhole=density*volumehole
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