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At an annual flower show, 6 different entries are to be arranged in a row. a) How many different arrangements of the entries ar...Asked by Rose
13. (4 pts) At an annual flower show, 6 different entries are to be arranged in a row.
a) How many different arrangements of the entries are possible?
b) If the owners of the 1st, 2nd, and 3rd place entries will be awarded prizes of $100, $50, and $25 respectively, how many ways can the prizes be awarded?
a) How many different arrangements of the entries are possible?
b) If the owners of the 1st, 2nd, and 3rd place entries will be awarded prizes of $100, $50, and $25 respectively, how many ways can the prizes be awarded?
Answers
Answered by
Damon
6 ways to put an entry in space 1 times
5 ways to put an entry in space 2 times
4 ways to put an entry in space 3 times
3 4
2 5
1 6
looks like 6! = 720
How many permutations of 6 taken 3 at a time? (They are permutations not combinations, because the order in the group of three matters)
n!/(n-r)!
where n is 6 and r is three
6!/(3)! = 6*5*4 = 120
5 ways to put an entry in space 2 times
4 ways to put an entry in space 3 times
3 4
2 5
1 6
looks like 6! = 720
How many permutations of 6 taken 3 at a time? (They are permutations not combinations, because the order in the group of three matters)
n!/(n-r)!
where n is 6 and r is three
6!/(3)! = 6*5*4 = 120
Answered by
Rose
Thank you Damon for all your help. You all are life savers.
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