Asked by elis
differentiate y=-4x^2cos x. i need to know the calculation work. (ans: 4x^2sinx - 8xcosx)
Answers
Answered by
Reiny
use the product rule
y = (-4x^2)(cosx_
dy/dx = (-4x^2)(-sinx) + (-8x)(cosx)
= 4x^2sinx - 8xcosx
y = (-4x^2)(cosx_
dy/dx = (-4x^2)(-sinx) + (-8x)(cosx)
= 4x^2sinx - 8xcosx
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