Asked by Josh
After 79 mins 20.0% of a compound has decomposed. What is the half life of this reaction assuming first-order kinetics?
Answers
Answered by
bobpursley
.2=e^(-.693*79/thl)
solve for thlife
take ln both sides
ln.2=-.693*79/thl
grab you calculator.
solve for thlife
take ln both sides
ln.2=-.693*79/thl
grab you calculator.
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